Multiprocessing by Message Passing MPI
Example 1.1 Integration with MPI Blocking Send/Receive
This example demonstrates parallel integration (see Example 1 for detail) via the following MPI library routines. Click on them for details:
#include <mpi.h>
#include <math.h>
#include <stdio.h>
float fct(float x)
{
return cos(x);
}
/* Prototype */
float integral(float a, int i, float h, int n);
void main(int argc, char* argv[])
{
/***********************************************************************
*
* This is one of the MPI versions on the integration example
* It demonstrates the use of :
*
* MPI_Init
* MPI_Comm_rank
* MPI_Comm_size
* MPI_Recv
* MPI_Send
* MPI_Finalize
*
* Dr. Kadin Tseng
* Scientific Computing and Visualization
* Boston University
* 1998
*
***********************************************************************/
int n, p;
float h, result, a, b, pi;
int myid, src, dest, tag;
MPI_Status status;
float my_result;
/* Starts MPI processes ... */
MPI_Init(&argc,&argv); /* starts MPI */
MPI_Comm_rank(MPI_COMM_WORLD, &myid); /* get current process id */
MPI_Comm_size(MPI_COMM_WORLD, &p); /* get number of processes */
pi = acos(-1.0); /* = 3.14159... */
a = 0.; /* lower limit of integration */
b = pi*1./2.; /* upper limit of integration */
n = 500; /* number of increment within each process */
dest = 0; /* define the process that computes the final result */
tag = 123; /* set the tag to identify this particular job */
h = (b-a)/n/p; /* length of increment */
my_result = integral(a,myid,h,n);
printf("Process %d has the partial result of %f\n", myid,my_result);
if(myid == 0) {
result = my_result;
for (src=1;src<p;src++) {
MPI_Recv(&my_result, 1, MPI_REAL, src, tag,
MPI_COMM_WORLD, &status); /* not safe */
result += my_result;
}
printf("The result =%f\n",result);
}
else
MPI_Send(&my_result, 1, MPI_REAL, dest, tag,
MPI_COMM_WORLD); /* send my_result to intended dest. */
MPI_Finalize(); /* let MPI finish up ... */
}
float integral(float a, int i, float h, int n)
{
int j;
float h2, aij, integ;
integ = 0.0; /* initialize integral */
h2 = h/2.;
for (j=0;j<n;j++) { /* sum over all "j" integrals */
aij = a + (i*n + j)*h; /* lower limit of "j" integral */
integ += fct(aij+h2)*h;
}
return integ;
}
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